physics
If a ball is thrown upwards at 20 ft/sec, the height h after t seconds is given by h = 16t^2 + 20t. How many seconds does it take for the ball to reach its maximum height, and what is this height?
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lee

at max height, Velocity is zero.
v=dh/dt=32t+20=0 t= 20/32 seconds
calculate h at this time.posted by bobpursley
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