# calculus

write it in the form of a+ib
(1+i)^2 (1-i)^3

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1. Hmmmm.

(1+i)(1-i)(1+i)(1-i)*(1-i)

taking them as pairs...

the first two give (1^-i^2) =2
so we have
2*2*(1-i)

can you take it from here?

Now if you want to do it in polar, the problem is
or

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