Algebra

The function h is defined by h(x)=x^(2)-x.


Find h(2x).

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  1. (2x)^2-2x=4x^2-2x

  2. Substitute 2x for x into the function, which would leave you:

    h(x)=(2x)^2-2x

    Factor out a 2x.

    H(x)=2x(x-1) then set 2x and x-1 both equal to 0.

    2x=0 x-1=0

    x= 0 x=1

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  3. My money is on bobpursley, big time!

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    posted by Reiny
  4. Thanks I agree Reiny

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    posted by Miranda

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