# Algebra

The function h is defined by h(x)=x^(2)-x.

Find h(2x).

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1. (2x)^2-2x=4x^2-2x

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2. Substitute 2x for x into the function, which would leave you:

h(x)=(2x)^2-2x

Factor out a 2x.

H(x)=2x(x-1) then set 2x and x-1 both equal to 0.

2x=0 x-1=0

x= 0 x=1

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3. My money is on bobpursley, big time!

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posted by Reiny
4. Thanks I agree Reiny

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posted by Miranda

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