A glucose (C6H12O6) solution is 2.5% glucose by mass. If the density of the
solution is 1.10 g/mL, what is the molarity of glucose/water solution?
How did you get the amount of water?
volume+ 1000/1.1=909 ml? I don't get this...
I understand how you got the water
you have 1000 total grams, the density is 1.1g/ml, so volume= 1000/1.1 ml
Oh... I get it now! Thank you very much. Your help is greatly appreciated.
To find the molarity of the glucose/water solution, you need to know the number of moles of glucose in the solution and the volume of the solution in liters.
First, let's calculate the mass of glucose in the solution. The solution is 2.5% glucose by mass, so if you have 100 grams of the solution, you will have 2.5 grams of glucose.
Next, we need to convert the mass of glucose to moles. To do this, we need to know the molar mass of glucose, which is the sum of the atomic masses of its elements: C (12.01 g/mol) x 6 + H (1.01 g/mol) x 12 + O (16.00 g/mol) x 6 = 180.18 g/mol.
Now we can calculate the number of moles of glucose using the mass of glucose and the molar mass of glucose:
moles of glucose = mass of glucose / molar mass of glucose
moles of glucose = 2.5 g / 180.18 g/mol
Next, we need to find the volume of the solution in liters. We know the density of the solution is 1.10 g/mL. Since density is mass per unit volume, we can rearrange the equation to solve for volume:
volume of solution = mass of solution / density of solution
Since the mass of the solution is not given, we can assume we have 100 mL (or 100 grams) of the solution, as mentioned earlier.
volume of solution = 100 g / 1.10 g/mL = 90.91 mL = 0.09091 L
Finally, we can calculate the molarity of the glucose/water solution using the number of moles of glucose and the volume of the solution:
Molarity = moles of solute / volume of solution (in liters)
Molarity = (2.5 / 180.18) mol / 0.09091 L
Now you can perform the final calculation to find the molarity of the glucose/water solution.
assume 1000grams. Then glucose is 25grams, and water 975 grams.
volume+ 1000/1.1=909 ml
molarity= (25/molmassglucose)/.909