Math

1) evaluate

integral of xe^3x dx

2) evaluate integral form 1 to 0 of 4e^2x dx

I just need help finding the anitderivative. Would it be 2e^2x?

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asked by Hannah
  1. u = 3x
    dx = (1/3) du

    (1/3) u e^u * (1/3) du
    = (1/9) u e^u du

    = (1/9) [ ue^u - e^u]

    = (1/9) [ 3x e^(3x) - e^(3x) ]

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    posted by Damon
  2. d/dx ( 2e^(2x) ) = 4 e^(2x) so yes

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    posted by Damon
  3. for number 2 how did you get 2e^2x?

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    posted by Hannah

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