solve
(4x^2+2x-4) - (x^2-5x-4)=
I came up with 3x^2+7 is my answer correct?
The first term 3x² is correct.
The next term should be
2x-(-5x)=7x
The third term is -4-(-4)=0 (as you had it)
So the answer is 3x²+7x.
You were close.
Thank you math mate
You're welcome!
To solve the expression (4x^2+2x-4) - (x^2-5x-4), you need to combine like terms.
First, distribute the negative sign to the terms inside the parentheses:
(4x^2 + 2x - 4) - (x^2 - 5x - 4) = 4x^2 + 2x - 4 - x^2 + 5x + 4
Next, combine the like terms of the same degree (i.e., terms with x^2, x, and constants):
(4x^2 - x^2) + (2x + 5x) + (-4 + 4) = 3x^2 + 7x
So, the correct simplified form of the expression is 3x^2 + 7x. Your answer, 3x^2 + 7, is incorrect because it is missing the x term.
Remember to always carefully combine like terms to arrive at the correct answer.