When 1500 joules of energy is lost from 0.12kg object the temperature decreases from 45 to 40 What is the specific heat of this object ? Of what material is the object made?

1,400

To find the specific heat of an object, we can use the formula:

Energy lost = (mass) x (specific heat) x (change in temperature)

Given:
Energy lost = 1500 joules
Mass = 0.12 kg
Change in temperature = 45°C - 40°C = 5°C

Substituting the values into the formula:

1500 joules = (0.12 kg) x (specific heat) x (5°C)

To find the specific heat, we rearrange the formula:

Specific heat = Energy lost / (mass x change in temperature)

Substituting the values:

Specific heat = 1500 joules / (0.12 kg x 5°C)

Specific heat = 1500 joules / 0.6 kg°C

Specific heat ≈ 2500 J/(kg°C)

Now, to determine the material of the object based on its specific heat, we can compare this specific heat value to known values for different materials. Common specific heat values for materials include:

- Water: 4186 J/(kg°C)
- Aluminum: 897 J/(kg°C)
- Iron: 450 J/(kg°C)

Based on the specific heat value of approximately 2500 J/(kg°C), the object is most likely made of a material other than water, aluminum, or iron. Without further information, it is difficult to determine the exact material.

To find the specific heat of an object, we can use the formula:

Q = mcΔT

where:
- Q is the energy lost or gained
- m is the mass of the object
- c is the specific heat of the material
- ΔT is the change in temperature

In this case, we are given:
- Q = 1500 Joules (energy lost)
- m = 0.12 kg (mass of the object)
- ΔT = 45°C - 40°C = 5°C (change in temperature)

Using the formula, we can rearrange it to solve for c:

c = Q / (m * ΔT)

Now we can plug in the values:

c = 1500 J / (0.12 kg * 5°C)

Simplifying the equation:
c = 1500 J / 0.6 kg°C

Therefore, the specific heat of the object is c = 2500 J/kg°C.

To determine the material that the object is made of, we need more information. The specific heat varies for different materials. You can find reference tables or use experimental data to match the specific heat value obtained with known materials.