While on the moon, the apollo astronauts enjoyed the effects on gravity so much smaller then that ont he earth. If neil armstrong jumped up on the moon with the initial speed
missing something?
To calculate the effect of gravity on Neil Armstrong's jump on the moon, we need to use the equation for free fall motion.
The equation for free fall motion is given by:
distance = (initial velocity * time) + (0.5 * acceleration * time^2)
Since Neil Armstrong is jumping upwards, the initial velocity (u) will be positive, and the acceleration due to gravity (g) will be negative on the moon. The time (t) can be assumed to be the amount of time he spends in the air during the jump.
On the moon, the acceleration due to gravity is approximately 1/6th of Earth's gravity, or 1.622 m/s^2. So, we can use this value for acceleration (a).
Now, let's assume Neil Armstrong's initial speed (u) is "x" m/s and the time he spends in the air is "t" seconds. We can now rewrite the equation as:
distance = (x * t) + (0.5 * (-1.622) * t^2)
At the highest point of the jump, the velocity becomes zero. Therefore, the final velocity (v) will be 0 m/s.
We can use this fact to find the time (t) it takes for Neil Armstrong to reach the highest point of his jump:
final velocity (v) = initial velocity (u) + (acceleration * time)
0 = x - (1.622 * t)
Simplifying the equation, we get:
x = 1.622 * t
Now, you can substitute this value of time into the previous equation to find the maximum height Neil Armstrong reaches on his jump.