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Chemistry e
The rusting of iron is represented by the equation 4Fe +3O2 --> 2Fe2O3. If you have a 1.50-mol sample of iron, how many moles of Fe2O3 will there be after the iron has rusted completely? a. 0.50 mol b. 0.75 mol c. 1.0 mol d. 1.50
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The overall reaction in a commercial heat pack can be represented as shown below. 4 Fe(s) + 3 O2(g) 2 Fe2O3(s) ΔH = -1652 kJ How much heat is released when 4.00 mol iron is reacted with excess O2? How much heat is released when
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Iron metal reacts with oxygen gas to produce iron(III) oxide. If you have 12.0 moles of iron, for complete reaction you need: (HINT you need the balanced chemical reaction!) A) 9.0 moles of O2 and produce 3.0 moles of Fe2O3 B) 9.0
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Am I correct? Deterioration of buildings, bridges, and other structures through the rusting of iron costs millions of dollars everyday. Although the actual process also requires water, a simplified equation (with rust shown as
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When iron (Fe) rusts (reacts with O2), the product is iron(III) oxide (Fe2O3). If 25 g Fe is reacted with 25 g O2 in a sealed container, what are the masses of Fe, O2 and Fe2O3 in the container after the reaction is complete? How
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An iron ore sample contains Fe2O3 together with other substances. Reaction of the ore with CO produces iron metal: αFe2O3(s)+βCO(g)→γFe(s)+δCO2(g) A)Balance this equation. B)Calculate the number of grams of CO that can react
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When 84.8 g of iron(III) oxide reacts with an excess of carbon monoxide, iron is produced. Fe2O3(s) + 3CO(g) ==> 2Fe(s) + 3CO2(g) what is the theoretical yield of iron?
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How many grams of iron can be made from 16.5g of Fe2O3 by the following equation: Fe2O3 + 3 H2 -----> 2 Fe + 3 H2O.
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Last Question Plz helppp:((im soo sleepy!!:(
1)The reaction between solid sodium and iron(III) oxide, Fe2O3(s), is one in a series of reactions that occurs when an automobile air bag inflates. 6Na(s) + Fe2O3(s) -> 3Na2o(s) + 2Fe(s) If 100.0 g of iron(III) oxide are used in
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Fe2O3(s) + 2Al(s)-> 2Fe(l) + Al2O3(s) What is the theoretical yield of iron if we begin the reaction with 10.5 g of Al (assume an excess of Fe2O3)
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Fe2O3(s) + 3 CO(g) −→ 2 Fe(s) + 3 CO2(g) Given: 2 Fe2O3(s) −→ 4 Fe(s) + 3 O2(g) ∆H = 1616.6 kJ/mol CO(g) −→ C(s) + 1 2 O2(g) ∆H = 110.5 kJ/mol C(s) + O2(g) −→ CO2(g) ∆H = −393.5 kJ/mol Answer in units of
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4Fe + 3O2 -> 2Fe2O3 + 1.65E3 kJ C) what is the enthalpy change for the formation of 23.6 g of iron(iii) oxide? I'm trying to understand thermochemical reactions and stoichiometry, so could you please tell me if this is correct?
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