Math

the concentration of a certain substance in our organism is given by the model Q9t) = Q(subscript 0) e^-0.1960t

a) what quantity of substance is present in the organism of this individual 3 hours after ingestion?

b) after how many hours will there only be 10% of this substance ingested by the individual?

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  1. Q(t) = Q0 e^-0.1960t
    where t=elapsed time in hours (Check, not mentioned in the question).
    So after three hours,
    Q(3) = Q0 e^(-0.1960*3)=?

    Q(t) = 0.9Q0
    or
    e^(-0.1960t)=0.9
    Take natural log:
    -0.1960t = ln(0.9)
    t=ln(0.9)/(-0.1960)=?

    I'll leave it to you to work on your calculator.

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