how do you Convert moles S2O3^-2 to moles I2
I have a feeling this is not the question you really want answered. I think I remember you asking about titration of Cu with S2O3. However, to answer your question:
2S2O3^-2 + I2 ==> 2I^- + S4O6^-2
Use the coefficients in the balanced equation to convert moles of one material to moles of another.
Let's say we have 0.5 M S2O3^-2 and we used 20 mL, then moles S2O3^-2 = M x L = 0.5M x 0.02L = 0.01 moles. Now to convert that to moles I2, we use
0.01 moles S2O3^-2 x (1 mole I2/2 moles S2O3^-2) = 0.01 x (1/2) = 0.005 moles I2.
To convert moles of S2O3^-2 to moles of I2, you need to use the balanced chemical equation that relates the two compounds. The balanced equation is:
2 S2O3^-2 + I2 -> 2 I^- + S4O6^-2
From the equation, you can see that for each mole of S2O3^-2, 1 mole of I2 is produced. Therefore, the conversion factor is 1 mole of I2 per 2 moles of S2O3^-2.
To convert moles of S2O3^-2 to moles of I2, you can use the following steps:
1. Determine the number of moles of S2O3^-2 you have.
2. Use the conversion factor of 1 mole I2 / 2 moles S2O3^-2 to convert from moles of S2O3^-2 to moles of I2.
Here is the step-by-step conversion using an example:
Example: If you have 0.5 moles of S2O3^-2, how many moles of I2 are there?
1. You have 0.5 moles of S2O3^-2.
2. Use the conversion factor:
0.5 moles S2O3^-2 x (1 mole I2 / 2 moles S2O3^-2) = 0.25 moles I2
Therefore, if you have 0.5 moles of S2O3^-2, you will have 0.25 moles of I2.
To convert moles of S2O3^-2 to moles of I2, you need to use the balanced chemical equation and the stoichiometric ratio between the two compounds.
Step 1: Write the balanced chemical equation.
2 S2O3^-2 + I2 → S4O6^-2 + 2 I^-
From the equation, you can see that the stoichiometric ratio between S2O3^-2 and I2 is 2:1. This means that for every 2 moles of S2O3^-2, you will have 1 mole of I2.
Step 2: Determine the number of moles of S2O3^-2.
Let's assume you have X moles of S2O3^-2.
Step 3: Use the stoichiometric ratio to calculate the number of moles of I2.
Since the ratio is 2:1, you can set up this proportion:
2 moles of S2O3^-2 / 1 mole of I2 = X moles of S2O3^-2 / Y moles of I2
Cross-multiplying gives you:
2Y = X
Divide both sides by 2:
Y = X/2
So, the number of moles of I2 is equal to half the number of moles of S2O3^-2.
In conclusion, to convert moles of S2O3^-2 to moles of I2, divide the number of moles of S2O3^-2 by 2.