solve first derivative of f(x)=-460+100Q-Q2 where Q=10
If:
f(x)= -460+100Q-Q^2
Then:
f´(x)=df/dQ=100Q+2Q=2*(50+q)
For Q=10
f´(x)=2*(50+10)=2*60=120
f(Q)= -460+100Q-Q^2
not f(x)
and
f´(Q)=df/dQ=100Q+2Q=2*(50+q)
f´(Q)=2*(50+10)=2*60=120
f´(Q)=df/dQ=100+2Q=2*(50+q)
f´(Q)=2*(50+10)=2*60=120
In google type: calc101
When you see list of results click on:
Calc101com Automatic Calculus,Linear Algebra and Polynomials
When page be open clik option: derivatives
When this page be open in rectacangle type:
-460+100Q-Q^2
In rectacangle with respect to:
type Q
in rectacangleand again with respect to: type Q
and click options DO IT
You will see solution step-by-step
By the way on this site you can practice any kind of derivation.
To solve for the first derivative of f(x), we need to calculate the derivative of the function with respect to x. However, in this case, we have an additional variable Q that depends on x.
Given that Q = 10, we can substitute Q into the function f(x) = -460 + 100Q - Q^2 to eliminate Q.
f(x) = -460 + 100(10) - (10)^2
= -460 + 1000 - 100
= -460 + 900
= 440
Now, we have simplified the function to f(x) = 440. Since the function is now a constant, the derivative with respect to x is always zero.
Therefore, the first derivative of f(x) = -460 + 100Q - Q^2, where Q = 10, is 0.