math

Find the values of c so that the intersection of y=-x+6 and y=x/3+c lies
strictly in the first quadrant (not on a coordinate axis).

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  1. Solve system of equations to get
    x and y in terms of c.
    For example:
    x=(18-3c)/4 >0 (in Q1)
    Solve for c from the inequality:
    18-3c > 0
    c<6

    Similarly, you'd get
    y=(3c+6)/4 > 0 (in Q1)
    so 3c+6>0
    c>2

    Combine the two conditions to get
    2<c<6

    Check all calculations.

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