math

6{[3(x 4)+16]-[3(4x-3)+4]}
how do I solve this expression I cant figure this out

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  1. What is: 3(x 4)?

    3(x+4) OR 3(x-4)

    If 3(x 4)=3(x+4) then:

    3(x+4)=3*x+3*4=3x+12

    3(x+4)+16=3x+12+16=3x+28

    3(4x-3)=3*4x-3*3=12x-9

    3(4x-3)+4=12x-9+4=12x-5

    3(x+4)+16-3(4x-3)+4=(3x+28)-(12x-5)=
    3x+28-12x-(-5)=3x+28-12x+5= -9x+33

    6{[3(x 4)+16]-[3(4x-3)+4]}=6*(-9x+33)=
    -6*9x+6*33= -54x+198

    If 3(x 4)=3(x-4) then:

    3(x-4)=3*x-3*4=3x-12

    3(x-4)+16=3x-12+16=3x+4

    3(4x-3)=3*4x-3*3=12x-9

    3(4x-3)+4=12x-9+4=12x-5

    3(x-4)+16-3(4x-3)+4=(3x+4)-(12x-5)=
    3x+4-12x-(-5)=3x+4-12x+5= -9x+9

    6{[3(x 4)+16]-[3(4x-3)+4]}=6*(-9x+9)=
    -6*9x+6*9= -54x+54

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