f(x)=2x²-Bx+4 and f(3)=13, what is the value of B?
Given
f(x)=2x²-Bx+4
f(3)=13 means
2(3)²-B(3)+4 = 13
Solve for B.
To find the value of B, we need to substitute the given value of f(x) into the equation and solve for B.
Given: f(x) = 2x² - Bx + 4
We are also given that f(3) = 13.
So, we substitute x = 3 and f(x) = 13 into the equation:
13 = 2(3)² - B(3) + 4
Simplifying:
13 = 18 - 3B + 4
Combine like terms:
13 = 22 - 3B
Now, we solve for B:
13 - 22 = -3B
-9 = -3B
Finally, divide both sides by -3 to isolate B:
-9/-3 = B
B = 3
Therefore, the value of B is 3.