If you do work on an object in 1/3 the usual time, your power output is ____ times the usual power output
W = Fd/t = F * d/(t/3) = F * d * 3/t.
Wo = 3 Times the usual.
To determine the power output in this scenario, we can use the equation:
Power = Work / Time
Let's assume the usual power output is P, and the usual time required to do the work is T.
If the work is done in 1/3 the usual time, the time required would be T/3.
Using the equation for power, we have:
Power = Work / Time = Work / (T/3)
Since the work done is the same in both cases, let's say it is W.
Thus, the equation becomes:
Power = W / (T/3)
To simplify further, we can multiply the numerator and denominator by 3:
Power = (W * 3) / T
This can be written as:
Power = (3W) / T
Since the usual power output is P, we can substitute P for Power:
P = (3W) / T
Therefore, if you do work on an object in 1/3 the usual time, your power output is 3 times the usual power output.
To calculate the power output, we need to know the amount of work done and the time taken. The formula for power is:
Power = Work / Time
Given that you do the work in 1/3 the usual time, we can say the time taken is 1/3 of the usual time, or just 1/3.
Using this information, we can calculate the ratio of the new power output to the usual power output:
New Power Output / Usual Power Output = (Work / Time) / (Work / (1/3)Time)
Simplifying this equation:
New Power Output / Usual Power Output = 1 / (1/3) = 3/1 = 3
Therefore, if you do work on an object in 1/3 the usual time, your power output is 3 times the usual power output.