please help!
find 3 consective numbers with a sum of 12. find three consective numbers with a sum of 45
3 + 4 + 5 = 12
If you post your answer for a sum of 45, we'll be glad to check your answer.
please help!
find 3 consective numbers with a sum of 12. find three consective numbers with a sum of 45
12/3 = 4 making the three numbers 3, 4 and 5.
45/3 =
Nice trick there tchrwill. But too bad it doesn't work if the question ask for an even number of consecutive numbers, you know, like ask for 4 consecutive instead of 3, or 5 or 7 or any odd number.
Nice trick there tchrwill. But too bad it doesn't work if the question ask for an even number of consecutive numbers, you know, like ask for 4 consecutive instead of 3, or 5 or 7 or any odd number.
Sorry Jake1234
Find 4 consecutive numbers that sum to 26.
26/4 = 6.5 makign the four numbers 5, 6, 7 and 8.
It does not work for odd numbers, i.e., find four consecutive number that sum to 29. or any odd number.
Finding a set of "n" consecutive numbers that total a given sum "N", given "n" and "N".
Sets of n consecutive numbers.
If both n and N are odd, N/n produces the middle number of the n numbers which is an odd number.
If n is odd and N is even, N/n produces the middle number of the n numbers which is an even number.
If both n and N are even, and N/n produces an even number, there is no solution.
If both n and N are even, and N/n ends in .5 (x.5), the middle two numbers of the n numbers are (x.5 - .5) and (x.5 + .5).
If n ts n is even and N is odd, there is no solution.
Sets of n consecutive even numbers:
N is obviously even.
If n is even, there are N/n numbers on both sides of N/n.
If n is odd, N/n isi the middle number of the n numbers.
Sets of n odd consecutive numbers:
If N/n is even, therre are N/n numbers on both sides of N/n.
If N/n is odd, N/n is the middle number of the n numbers.
1. 4
To find three consecutive numbers with a sum of 12, we can follow these steps:
1. Let's represent the first number as "x". Since the numbers are consecutive, the second number would be "x + 1" and the third number would be "x + 2".
2. Set up an equation with the sum of the three numbers: x + (x + 1) + (x + 2) = 12.
3. Simplify the equation: 3x + 3 = 12.
4. Subtract 3 from both sides of the equation: 3x = 9.
5. Divide both sides of the equation by 3: x = 3.
6. Now that we have the value of x, substitute it back into the equation to find the three consecutive numbers: 3 + 4 + 5 = 12.
Therefore, the three consecutive numbers with a sum of 12 are 3, 4, and 5.
Now let's move on to finding three consecutive numbers with a sum of 45.
1. Let's represent the first number as "x". Since the numbers are consecutive, the second number would be "x + 1" and the third number would be "x + 2".
2. Set up an equation with the sum of the three numbers: x + (x + 1) + (x + 2) = 45.
3. Simplify the equation: 3x + 3 = 45.
4. Subtract 3 from both sides of the equation: 3x = 42.
5. Divide both sides of the equation by 3: x = 14.
6. Now that we have the value of x, substitute it back into the equation to find the three consecutive numbers: 14 + 15 + 16 = 45.
Therefore, the three consecutive numbers with a sum of 45 are 14, 15, and 16.