tori wants to increase the tempreature of 500 grams of water from 20 degrees celcius to 100 degrees celecius if the specific heat of water is 4.18j/g. degrees celcius how much heat is needed ?
Q=mxcx(temperature final-temperature initial) , next subtitute values; Q=500gx4.18J/g*Cx(100-20)*C, then cross out g with g and *C with *C . Multiply 500x4.18J ,and subtract 100-20 like this q=500x4.18Jx80=2090x80=167200J . Round to the significant figure will be 167J, that is how much heat is needed. I hope tis can help.
same song, second verse. And celcius should be celsius.
To calculate the heat needed to increase the temperature of a substance, we can use the formula:
Q = m * c * ∆T
where:
Q is the heat (in joules),
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in joules per gram.°C), and
∆T is the change in temperature (in °C).
In this case, Tori wants to increase the temperature of 500 grams of water from 20°C to 100°C, and the specific heat of water is 4.18 J/g.°C.
Substituting the values into the formula, we have:
Q = 500 g * 4.18 J/g.°C * (100°C - 20°C)
Let's calculate this:
Q = 500 g * 4.18 J/g.°C * 80°C
Q = 167,200 J
Therefore, Tori would need 167,200 Joules of heat to increase the temperature of 500 grams of water from 20°C to 100°C.