What is the approximate thermal energy in kJ/mol of molecules at 275° C
To calculate the approximate thermal energy in kJ/mol of molecules at a given temperature, you can use the equation:
E = (3/2) * R * T
Where:
- E is the thermal energy (in J/mol)
- R is the gas constant (8.314 J/(mol·K))
- T is the temperature (in Kelvin)
To convert the temperature from Celsius to Kelvin, you add 273.15.
Let's calculate:
T = 275 + 273.15 = 548.15 K
E = (3/2) * 8.314 J/(mol·K) * 548.15 K
E ≈ 6.92 kJ/mol
Therefore, the approximate thermal energy in kJ/mol of molecules at 275° C is approximately 6.92 kJ/mol.
To calculate the approximate thermal energy in kilojoules per mole (kJ/mol) of molecules at a given temperature, you need to use the equation:
Thermal energy (kJ/mol) = (3/2) * R * Temperature
Where:
- R is the gas constant, which is approximately 8.314 J/(mol·K)
- Temperature is in Kelvin
To convert the given temperature of 275°C to Kelvin:
Temperature (K) = 273.15 + Temperature (°C)
= 273.15 + 275
= 548.15 K
Substituting the values into the equation:
Thermal energy (kJ/mol) = (3/2) * 8.314 J/(mol·K) * 548.15 K
= 623.4 J/(mol·K) * 548.15 K
= 341,076.11 J/mol
To convert Joules to kilojoules, divide by 1000:
Thermal energy (kJ/mol) = 341,076.11 J/mol / 1000
≈ 341.08 kJ/mol
Therefore, the approximate thermal energy in kJ/mol of molecules at 275°C is approximately 341.08 kJ/mol.