# Chemistry II

At a certain temperature, Kc = 33 for the reaction:

H2(g) + I2(g) 2HI(g)

Assume that the initial concentrations of both H2 and I2 are 6.00 x 10-3 mol/L. Find the concentration of each reactant and product at equilibrium.

1. 2
1. You need to insert the arrow to know the difference between products and reactants. You have the equation, set up an ICE chart.
....................H2 + I2 ==> 2HI
...initial........0.006..0.006...0
change..............-x....-x.....2x
equilibrium.....0.006-x...0.006-x...2x

Now substitute into the Kc expression of
Kc = 0.33 = (HI)^2/(H2)(I2)
Solve for x and calculate each of the final concns. Post your work if you get stuck.

posted by DrBob222
2. X=1.97406×10 power of -3 .then what is the reactant and product of equilibrium .can't understand actually .

posted by ina

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