A 10-kg duffle bag is undergoing a vertical acceleration of 0.65 m/s2 (positive for up, negative for down), while its owner is holding it with an upward force. What is the magnitude of this force?

force= mg+ma

12.2

9.38 it's 10.05

=4.26

To find the magnitude of the force exerted by the owner on the duffle bag, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.

The given mass of the duffle bag is 10 kg, and the vertical acceleration is 0.65 m/s2. Since the force is acting in the upward direction, we can assume it is positive.

Using the formula F = m * a, where F is the force, m is the mass, and a is the acceleration, we can substitute the values:

F = 10 kg * 0.65 m/s2
F = 6.5 N

Therefore, the magnitude of the force exerted by the owner on the duffle bag is 6.5 Newtons.