Need to prepare a lab that requires 1000ml of 1.0M HCl. You find some 3 M HCl to work with.
What do you need and how would you work it out?
To prepare 1000 ml of 1.0M HCl using the 3 M HCl solution, you will need to calculate the volume of the 3 M HCl solution required and then dilute it to a final volume of 1000 ml.
Here's how you can work it out:
Step 1: Use the formula for dilution:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution
V1 = initial volume of the solution
C2 = final concentration of the solution
V2 = final volume of the solution
Step 2: Plug in the values:
C1 = 3 M (initial concentration)
V1 = ? (initial volume of the 3 M HCl solution)
C2 = 1.0 M (final concentration)
V2 = 1000 ml (final volume required)
(3 M)(V1) = (1.0 M)(1000 ml)
Step 3: Rearrange the equation and solve for V1:
V1 = (1.0 M)(1000 ml) / 3 M
V1 = (1000/3) ml ≈ 333.33 ml
So, you will need approximately 333.33 ml of the 3 M HCl solution.
Step 4: Once you have measured out 333.33 ml of the 3 M HCl solution, transfer it to a suitable container (such as a volumetric flask) and then dilute it with distilled water to bring the total volume to 1000 ml.
By following these steps, you can prepare 1000 ml of 1.0M HCl using the 3 M HCl solution.