Find the equation of the line.
find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-8, -6) and (x2, y2) = (0, 0)
slope 0-(-6)/0-(-8)= 3/4
how would I write it?
y=3/4x or y=3/4x+0 ?
y = ax + b
m = 3/4
y = 3/4 x + b
You need to find b for this equation.
Substitute one of the given points into your equation and solve for b.
Then use that b value for your equation.
I don't get a value for b, What am I missing?
You were given the points,
(x1, y1) = (-8, -6) and (x2, y2) = (0, 0)
y = 3/4 x + b
Use one of the given points, for example,
(-8, -6)
Solve for b
-6 = 3/4(-8) + b
b = 0
Therefore, the equation is
y = 3/4 x + 0
y = 3/4 x
I guess I miss-understood you. I didn't realize that you had already found the b value to be zero. (Since you didn't state that b = 0 originally). I shouldn't have assumed.
Ok thanks
To find the equation of the line in the form y = ax + b, where a is the slope and b is the y-intercept, you need to first calculate the slope (a) using the given points and then substitute the value of a into the equation.
Given points: (x1, y1) = (-8, -6) and (x2, y2) = (0, 0)
To find the slope (a), you can use the formula:
a = (y2 - y1) / (x2 - x1)
Substituting the values:
a = (0 - (-6)) / (0 - (-8))
a = 6 / 8
a = 3/4
Therefore, the equation of the line is:
y = (3/4) x + b
Now, to find the value of b, you need to substitute the coordinates of one of the points into the equation. Let's use point (x1, y1) = (-8, -6).
-6 = (3/4)(-8) + b
-6 = -6 + b
b = 0
Therefore, the final equation of the line is:
y = (3/4) x + 0
Which simplifies to:
y = (3/4) x