math

find the length width and area of an object where the perimeter is fixed at 20 meters

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  1. What kind of object?

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    Ms. Sue
  2. a rectangle

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  3. P = 2L + 2W

    30 = 2(5) + 2(5)
    or
    20 = 2(4) + 2(6)
    or
    20 = 2(3) + 2(7)
    or
    20 = 2(2) + 2(8)
    or
    20 = 2(1) + 2(9)

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    Ms. Sue
  4. Correction:

    the first combination should be:

    20 = 2(5) + 2(5)

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    Ms. Sue

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