A copper calorimeter can with mass .100 kg contains .160 kg of water and .018 kg of ice in thermal equilibrium at atmospheric pressure. If .750 kg of lead at a temperature of 255 degrees Celsius is dropped into the can what is the final temperature of the system if no heat is lost to the surroundings?

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  1. The sum of all the heats gained is zero (some of the heats gained will be negative, as in heat lost).

    Heatgainedwater+ heatgainedlead+ heatgained calorimeter+ heat gained ice=0
    mw*cw*(Tf-0) + ml*cl*(Tf-255) + mc*cc*(tf-0) + massice*latentheatfusionice =0

    Solve for Tf

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