How do you solve for 4y+8=1-5(3y-10)!
4y+8=1-5(3y-10)
Is the ! part of your problem?
No it was a typo sorry
Thanks.
4y+8=1-5(3y-10)
4y + 8 = 1 - 15y + 50
19y = 51 - 8
19y = 43
y = 43/19 = 2.263
Here's another interpretation of your problem. Parentheses and brackets do make a difference.
4y+8=1-5(3y-10)
4y + 8 = -4(3y-10)
4y + 8 = -12y + 40
8y = 32
y = 4
To solve the equation 4y + 8 = 1 - 5(3y - 10), you can follow these steps:
Step 1: Distribute the -5 to the terms inside the parentheses:
4y + 8 = 1 - 15y + 50
Step 2: Combine like terms:
4y + 8 = -15y + 51
Step 3: Move all the terms with y to one side of the equation. To do this, add 15y to both sides:
4y + 15y + 8 = -15y + 15y + 51
19y + 8 = 51
Step 4: Move the constant term to the other side of the equation. To do this, subtract 8 from both sides:
19y + 8 - 8 = 51 - 8
19y = 43
Step 5: Solve for y by dividing both sides of the equation by 19:
(19y)/19 = 43/19
y = 43/19
Therefore, the solution to the equation 4y + 8 = 1 - 5(3y - 10) is y = 43/19.