for each of the following balanced chemical equations write all possible mole ratios.
Mg+ 2HF---> MgF^2+ H^2
To determine the mole ratios for the given balanced chemical equation, we need to compare the coefficients of the reactants and products. Let's break down the given equation into its individual components:
Reactants:
Mg + 2HF
Products:
MgF₂ + H₂
Now, let's examine the coefficients of each compound:
Reactants:
Mg - coefficient of 1
HF - coefficient of 2
Products:
MgF₂ - coefficient of 1
H₂ - coefficient of 1
To find the mole ratios, we compare the coefficients of the compounds involved in the reaction. In this case, we compare the coefficients of the reactants (Mg and HF) and the coefficients of the products (MgF₂ and H₂).
Mole ratio between Mg and HF:
From the balanced equation, we can see that the coefficient of Mg is 1, and the coefficient of HF is 2. Therefore, the mole ratio of Mg to HF is 1:2.
Mole ratio between Mg and MgF₂:
Since both Mg and MgF₂ have a coefficient of 1 in the balanced equation, the mole ratio between Mg and MgF₂ is 1:1.
Mole ratio between MgF₂ and H₂:
Similar to the previous case, both MgF₂ and H₂ have a coefficient of 1, so the mole ratio between MgF₂ and H₂ is also 1:1.
To summarize:
Mole ratio between Mg and HF: 1:2
Mole ratio between Mg and MgF₂: 1:1
Mole ratio between MgF₂ and H₂: 1:1
These are the three possible mole ratios for the given balanced chemical equation.