Write out all the mole ratios of Al + H2SO4 —> Al2(So4)3 + H2 there are 5 in total
I assume you want it for the balanced equation so
2Al + 3H2SO4 —> Al2(So4)3 + 3H2
1 mol Al to 1 mol Al2(SO4)3
2 moles Al to 3 moles H2
2 moles Al to 3 mols H2SO4
3 mols H2SO4 to 1 mol Al2(SO4)3
There is also 1 mol Al2(SO4)3 to 3 mol H2
1 mole H2SO4 to 1 mol H2
bro help can you tell me all possible mole ratios 🙏🙏🙏
nevermind im so fricking stupid LMAOOOO
why did it censor st*pid and lm*o bruh
if you reading this hope you have an awesome day, good luck with your chemistry hw
To determine the mole ratios, we need to balance the chemical equation first. Let's start by balancing the elements on both sides of the equation:
Al + H2SO4 → Al2(SO4)3 + H2
The equation is unbalanced because we have one aluminum (Al) atom on the left side and two on the right side. To balance this, we need a coefficient of 2 in front of Al on the left side:
2Al + H2SO4 → Al2(SO4)3 + H2
Now, let's balance the sulfur (S) atoms. On the left side, we have one sulfur atom, and on the right side, we have three sulfur atoms. To balance this, we need a coefficient of 3 in front of H2SO4:
2Al + 3H2SO4 → Al2(SO4)3 + H2
The equation is now balanced. We can write out the mole ratios by comparing the coefficients of the balanced equation:
2 moles of Al : 3 moles of H2SO4
2 moles of Al : 1 mole of Al2(SO4)3
2 moles of Al : 1 mole of H2
Therefore, the mole ratios of the balanced equation are as follows:
- 2 moles of Al : 3 moles of H2SO4
- 2 moles of Al : 1 mole of Al2(SO4)3
- 2 moles of Al : 1 mole of H2
In total, there are three mole ratios in the balanced equation.