Physical science

A ball thrown upward reaches a height of 13m. How much time did it take to get to this height? How much time will take to fall to the ground?

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  1. consider energy.
    InitialKineticEnergy=finalPotentialEnergy
    1/2 mv^2=mg*13

    V =sqrt(2*9.8*13) that is the initial velocity.
    the average velocity going up is half that, so time up= 12/(1/2 sqrt(2*9.8*13)

    grab your calculator.

    Time down is the same as time up.

  2. yhtrh

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