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Chemistry

One type of sunburn occurs on exposure to UV light wavelength in the vicinity of 325nm.
How many photons are in 1.00 mJ burst of this radiation?

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Daisy

  1. E = hc/lambda
    h = Planck's constant = 6.626 x 10^-34 J*s.
    c is speed of light = 3 x 10^8 m/s.
    lambda is 325 nm. Put this in meters.
    E = Joules for 1 photon = xx.
    Then (xxJ/1 photon) = (1.00 mJ/?)
    Solve for ?. Be sure and put 1.00 mJ in as J.

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    DrBob222

  2. 1.64*10^15

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    Anonymous

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