How do I simply 4^-1x^0/y^-1
possible answers:
1/4y
4y
y/4
4
I really don't get these- but I think it might be y/4 because you take the negative to the top and the negative to the bottom, right?
remember that x^(-a) = 1/x^a
and a^0 - 1 for all a>0
4^-1x^0/y^-1
= (1/4)(x^0)(1/y)
= (1/4)(1)(1/y)
= 1/(4y)
(they should not have written the answer as 1/4y , it would mean (1/4) y )
The way you explained it, I can understand it-the way my teacher explained it-I was still confused
Thank you very much
To simplify the expression 4^-1x^0/y^-1, we can use the following rules:
1. Any number or variable raised to the power of 0 is equal to 1.
2. To divide two numbers with the same base raised to different exponents, subtract the exponent in the denominator from the exponent in the numerator.
Let's break down the expression step by step:
1. Starting with 4^-1, we know that any number raised to the power of -1 is the reciprocal of that number. So, 4^-1 is equal to 1/4.
2. Next, we have x^0. As mentioned earlier, any number raised to the power of 0 is equal to 1. Therefore, x^0 equals 1.
3. Moving on to y^-1, we apply the same logic as with 4^-1. Any variable raised to the power of -1 is equal to the reciprocal of that variable. Thus, y^-1 is equal to 1/y.
Now, let's substitute these simplified values back into the original expression:
1/4 * 1 * (1/y)
Simplifying further, we can multiply the numerators together and the denominators together:
(1 * 1)/(4 * y)
Finally, simplifying the expression, we get 1/(4y). Therefore, the answer is "1/4y".