I posted this earler and you gave me help, could you please check what I did?

Thank you

If a car drives off a 40 m high cliff with a horizontal velocity of 15 m/s, how far from the base of the cliff will the car strike the ground? Could someone help with the equation, please

Physics - bobpursley, Sunday, January 2, 2011 at 4:30pm
How long does it take to fall 40 m?

h= 1/2 g t^2
solve for t.

Now, given that time in the air, how far did the car travel horizontally?
distance= 15*t

Physics-Please check - JessieLynne, Sunday, January 2, 2011 at 4:39pm
So I say:
40 m = 1/2 (9.8) * t^2
40/4.9 = 8.16(t^2)
sqrt of 8.16 = 2.86 = time
15 * 2.86 = 42.9 m for how far from the base of the cliff the car stuck the ground

Is this correct?
Thank you for helping-
I'm homeschooled and trying to learn Physics on my own

3 answers

yes.

Thank you

Let's check your solution step by step.

First, you correctly set up the equation to find the time it takes for the car to fall 40 meters:

h = 1/2 gt^2

Substituting the given values:

40 = 1/2 (9.8) * t^2

Simplifying further:

40/4.9 = t^2

The next step is to take the square root of both sides:

sqrt(40/4.9) = t

Calculating this expression gives you:

t ≈ 2.858

So far, your calculations are correct.

Now, you need to find the horizontal distance traveled by the car during this time. You correctly set up the equation:

distance = 15 * t

Substituting the value of t:

distance ≈ 15 * 2.858

Calculating this expression gives you:

distance ≈ 42.87

Now, let's compare your answer with the correct solution.

The correct answer is approximately 42.9 meters, while you calculated approximately 42.87 meters. Your answer is very close to the correct value, so it seems like you made a small rounding error in one of the calculations.

Overall, your solution is correct, with a very minor error in the final answer due to rounding. Great job!