a hockey puck is given the initial speed of 10 m/s. If the coefficient of kinetic friction between the ice and puck is 0.10, how far will the puck slide before stopping?

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  1. KE= energy in friction
    1/2 m v^2=mu*mg*distance
    solve for distance.

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  2. Ffg

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  3. What you wanna do is snort a line, smoke a J and look beyond what you see

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  4. HAHA!

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  5. f = ma
    u(k) * f(normal) = m*a
    u(k) *m*g=m*a
    u(k) *g =a
    a = 0.10 * 9.81m/s^2 = 0.981 m/s^2
    this is defined to be a negative acceleration

    v = u + a*t
    so t = (v-u)/a
    and x = t * (v+u)/2
    so together x = (v+u)(v-u)/2a
    where x = distance, v = final speed, u = initial speed, t = time, a = acceleration

    substitute in our known values:
    x = (0+10)(0-10)/(2*-0.981)
    x = 50/0.981 = 50.97m

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