math

compute x+y, given the linear system with T is not = to 1 and with the ordered pair (x,y) as solution: x+2y=3
and Tx+(T+1)y=T+2

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  1. multiply the first by T
    Tx + 2Ty = 3T
    Tx + (T+1)y = T+2
    subtract ....
    2Ty - (T+1)y = 3T - (T+2)
    (T-1)y = 2T-2
    y = 2(T-1)/(T-1) = 2

    back in the first
    x + 4 = 3
    x = -1

    then x+y = -1+2 = 1

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    posted by Reiny

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