If humans produce a 10mm wavelengh, what is their frequency? Find the energy emitted from humans off of the wavelength given.
frequency*lambda=3E8
frequency=3E8/.001= 3E11 hz
Can you help me find the energy emitted off of humans? It is a two parted question.
energy= planck's constant*frequency.
Thank you so much!
h*frequency is the energy per photon
Humans emit a range of electromagnetic frequencies, including 10 mm, but the maximum is emitted around 10 micrometers, not 10 millimeters. The spectrum is approximatley that of a 300 K black body.
If you are talking about deBroglie (matter) waves, that is an entirely different topic. The deBroglie wavelength of matter depends upon its momentum. deBroglie waves do not travel at the velocity of light. They have a phase velocity that is higher and a group velocity that is lower than c.
I am not quite sure what your question is getting at.
To find the frequency of a wavelength, you can use the equation:
c = λ * f
where:
c is the speed of light (approximately 3 x 10^8 m/s)
λ is the wavelength in meters
f is the frequency in hertz (Hz)
In this case, you provided the wavelength as 10 mm, which needs to be converted to meters by dividing by 1000:
λ = 10 mm / 1000 = 0.01 m
Now we can rearrange the equation to solve for the frequency (f):
f = c / λ = (3 x 10^8 m/s) / (0.01 m) = 3 x 10^10 Hz
Therefore, the frequency of a 10 mm wavelength is 3 x 10^10 Hz.
To find the energy emitted, we can use Planck's equation:
E = h * f
where:
E is the energy
h is Planck's constant (approximately 6.626 x 10^-34 J·s, joule-seconds)
f is the frequency in hertz (Hz)
Using the frequency we calculated earlier:
E = (6.626 x 10^-34 J·s) * (3 x 10^10 Hz)
Calculating that, we get:
E = 1.9878 x 10^-23 J
Therefore, the energy emitted from humans with a 10 mm wavelength is approximately 1.9878 x 10^-23 joules.