I am not thinking straight anymore and this is due by 9:00pm. My brain feels a little fried at this point. I have been at it all day. Can someone please help me!

(a) An object is placed in front of a convex mirror. Draw a convex mirror (radius of curvature = 15 cm) to scale, and place an object 28 cm in front of it. Make the object height 4 cm. Using a ray diagram, locate the image and measure its height. (Do this diagram on paper. Your instructor may ask you to turn in this work.)
cm (image location, include sign)
cm (image height, include sign)

(b) Now move the object closer to the mirror, so the object distance is 5 cm. Again, locate its image using a ray diagram. .
cm (image location, include sign)
cm (image height, include sign)

(c) As the object moves closer to the mirror, does the magnitude of the image distance become larger or smaller?
larger
smaller
stays the same

(d) As the object moves closer to the mirror, does the magnitude of the image height become larger or smaller?
larger
smaller
stays the same

(e) What is the ratio of the image height when the object distance is 5 cm to that when the object distance is 28 cm? Give your answer to one significant figure.
h5 cm / h28 cm =

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1. The first four are ray diagrams.

http://www.glenbrook.k12.il.us/GBSSCI/PHYS/Class/refln/u13l4b.html

answer e can be done on the ray diagram also, but there is a formula you can use to check it.

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bobpursley

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