Write an equation of the line that passes through the given point and is parrel to the given line.
1. (-1,3) Y=2x+2
I'm thinking that you just plug in -1 and 3 for x and y.
So, 3=2(-1)+2
Correct?
Please help me. :)
Thank you
-Allyson
Nope: Y=mx+ b is the general form. Plug in (-1,3) to get
3=-m+b
Now parallel means the same slope (y=2x+2, slope 2)
-3=-2+b
b=-1
equation of line? y=2x-1
Thank you.
Yes, you're on the right track! To find the equation of a line that is parallel to a given line, you need to use the same slope as the given line. In this case, the given line has a slope of 2. So the equation of the line parallel to this line will also have a slope of 2.
Now, you have the point (-1,3) that the line passes through. Using the point-slope form of a linear equation, we can write the equation as:
y - y₁ = m(x - x₁)
where (x₁, y₁) is the given point and m is the slope.
Plugging in the values, we have:
y - 3 = 2(x - (-1))
Simplifying, we have:
y - 3 = 2(x + 1)
Now, let's simplify further:
y - 3 = 2x + 2
Finally, rearrange the equation to put it in slope-intercept form (y = mx + b):
y = 2x + 5
So, the equation of the line that passes through the point (-1,3) and is parallel to the line y = 2x + 2 is y = 2x + 5.