Chem 22

balance molecular formula, total ionic formula and net ionic formula of Sr(NO3)2 + Al2(SO4)3. Thank you

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asked by Ivy
  1. 3Sr(NO3)2(aq) + Al2(SO4)3(aq) ==> 3SrSO4(s) + 2Al(NO3)3

    Split positive from negative ions for the total iionic formula. You can do that, start by
    3Sr^+2(aq) + 6NO3^-(aq) + 2Al^+3(aq) + 3SO4^-2(aq)==> etc.

    net ionic equation.
    3Sr^+2(aq) + 3SO4^-2(aq) ==> 3SrSO4(s)

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    posted by DrBob222

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