Rationalize the denominator. Assume all variables represent positive numbers?
- 245x3
y5
Online "^" is used to indicate an exponent. Your presentation is unclear.
-245 * x^3/y^5?
-245x^3 * y^5?
(-245x^3)/y^5?
Since this is not my area of expertise, I searched Google under the key words "unsaturated alkenes" to get these possible sources:
http://www.google.com/search?client=safari&rls=en&q=algebra+rationalize+deonminator&ie=UTF-8&oe=UTF-8
In the future, you can find the information you desire more quickly, if you use appropriate key words to do your own search. Also see http://hanlib.sou.edu/searchtools/.
To rationalize the denominator, we need to eliminate any radicals or fractional exponents in the denominator, in this case, y^5.
To do this, we will multiply both the numerator and the denominator by the same expression that will result in eliminating the radical or fractional exponent in the denominator.
In this case, we want to eliminate y^5, which has a fractional exponent. To eliminate the fractional exponent, we need to multiply by y^(-5), which is the reciprocal of y^5. This will result in y^(-5) * y^5 = 1, effectively canceling out the y^5 term in the denominator.
So, to rationalize the denominator, we can multiply both the numerator and denominator by y^(-5):
((245x^3) * y^(-5)) / (y^5)
Now, let's simplify this expression:
First, let's simplify the numerator by multiplying the coefficients:
245x^3 * y^(-5) = 245x^3/y^5
Now, let's simplify the denominator, using the fact that y^(-5) is the same as 1/y^5:
1/y^5
Finally, let's combine the simplified numerator and denominator:
(245x^3) / (y^5 * 1/y^5)
This simplifies to:
(245x^3 * y^5) / 1
So, the rationalized expression is:
245x^3 * y^5