what is the variation of pressure in the sound wave if the sound intensity is 3.85x10^-8 W/m^2 the speed of sound is 343 m/s and the density of air is 1.2 kg/m3?
To find the variation of pressure in a sound wave, you can use the formula:
Pressure Variation (ΔP) = √(2 x Intensity x Density x Speed of Sound)
Given:
Sound Intensity (I) = 3.85x10^-8 W/m^2
Speed of Sound (v) = 343 m/s
Density of Air (ρ) = 1.2 kg/m^3
Substituting these values into the formula, we get:
ΔP = √(2 x (3.85x10^-8) x 1.2 x 343)
First, multiply the numbers inside the square root:
ΔP = √(2 x 4.62x10^-8 x 343)
Next, multiply the result by 2:
ΔP = √(9.24x10^-8 x 343)
Multiplying these numbers further, we get:
ΔP = √(3.1692x10^-5)
Taking the square root of 3.1692x10^-5, we find:
ΔP ≈ 0.005637 Pa
Therefore, the variation of pressure in the sound wave is approximately 0.005637 Pa.