Solve for v1.
O.500km/v1+3.50km/2v1=0.250h
(2.25 km)/v1 = 0.25 h
v1 = 9 km/h
h would have to have dimensions of time for this to make any sense. I assume the "h" means hours in this case
How did you get 2.25/v1?
I did the algebra, combining the two terms on the left.
3.50km/(2v1) = 1.75km/v1
Add 0.50km/v1 to that
Thanks I don't know I could forget that. Is this like algebra?
Yes. You need to do some algebra to get the answer. You don't need any physics.
To solve for v1 in the given equation, we will first simplify the equation by finding a common denominator for the fractions and combining like terms. Then, we can solve for v1.
The given equation is:
0.500km/v1 + 3.50km/2v1 = 0.250h
To find the common denominator for the fractions, we need to find the least common multiple (LCM) of 1 and 2v1, which is 2v1. Therefore, we need to multiply the first fraction by 2/2 to get a common denominator:
(0.500km)/(v1) + (3.50km)/(2v1) = 0.250h
(1km)/(2v1) + (3.50km)/(2v1) = 0.250h
Now, we can combine the fractions:
[(1km) + (3.50km)]/(2v1) = 0.250h
(4.50km)/(2v1) = 0.250h
Next, we can divide both sides of the equation by (2v1) to isolate the variable v1:
(4.50km)/(2v1) / (0.250h) = 1
(4.50km)/(0.250h) = 2v1
18km/h = 2v1
Finally, divide both sides of the equation by 2 to solve for v1:
18km/h / 2 = v1
9km/h = v1
Therefore, the solution is v1 = 9 km/h.