A 0.580-kg rock is tied to the end of a string and is swung in a circle with a radius of 0.500 meters. The velocity of the rock is 4.50 m/s. What is the centripetal force acting on the rock?
how do i find centripetal force??
Centripetal force = M V^2/R
M is the mass, etc.
The subject is called physics.
A 0.580-kg rock is tied to the end of a string and is swung in a circle with a radius of 0.500 meters. The velocity of the rock is 4.50 m/s. What is the centripetal force acting on the rock?
To find the centripetal force acting on the rock, you can use the formula:
Centripetal Force (F) = (Mass (m) × Velocity^2 (v^2)) / Radius (r)
Given:
Mass (m) = 0.580 kg
Velocity (v) = 4.50 m/s
Radius (r) = 0.500 m
Now substitute the given values into the formula:
F = (0.580 kg × (4.50 m/s)^2) / 0.500 m
Firstly, square the velocity:
F = (0.580 kg × 20.25 m^2/s^2) / 0.500 m
Next, multiply the mass and the squared velocity:
F = 11.745 kg × m/s^2 / 0.500 m
Finally, divide the product by the radius:
F = 23.49 N
Therefore, the centripetal force acting on the rock is 23.49 Newtons (N).
To find the centripetal force acting on an object, you can use the centripetal force formula:
Centripetal force (F) = (mass of the object) × (velocity squared) / (radius of the circular path)
In this case, you are given the following information:
Mass of the rock (m) = 0.580 kg
Velocity of the rock (v) = 4.50 m/s
Radius of the circular path (r) = 0.500 m
Now you can substitute these values into the formula and calculate the centripetal force:
F = (0.580 kg) × (4.50 m/s)^2 / (0.500 m)
First, square the velocity:
F = (0.580 kg) × (20.25 m^2/s^2) / (0.500 m)
Now, divide the squared velocity by the radius:
F = (0.580 kg) × (20.25 m^2/s^2) / (0.500 m)
= 11.715 kg · m/s^2
Therefore, the centripetal force acting on the rock is approximately 11.715 N.