For this question can u please explain steps 3 and 4
4.0 g of ferrous ammonium sulphate, FeS04(NH4)2 SO4 6H20, is used. The oxalate is in excess, calculate the theoretical yield of the iron complex. Can someone please show me how to calculate a question like this please?
Thank you
1. Write the equation and balance it.
2. Convert 4.0 g of the ferrous ammonium sulfate to moles. #moles = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles of the ferrous ammonium sulfate to moles of the iron complex.
4. Finally, convert moles of the iron complex to grams. # grams = moles x molar mass. The number of grams of the iron complex is the theoretical yield.
Have you the balanced equation? If you have then step 3 is the easy step.
Lets say that the balanced reaction is
2A +3B-> 2C +D
this means that 2 moles of A yields 2 moles of C and one mole of D. So if we start with 1 mole of then this will form 1 mole of C and 0.5 mole of D. Or if we start with 0.2 mole of A then we get 0.2 mole of C and 0.1 mole of D.
For part 4. If we get M moles as the answer to part 3 then the mass of complex is
mass = M x molar mass of complex.
would my final answer be 3.2 g
Step 3: Using the coefficients in the balanced equation, convert moles of the ferrous ammonium sulfate to moles of the iron complex.
In this step, you need to refer to the balanced equation for the reaction between the ferrous ammonium sulfate and the oxalate.
Let's say the balanced equation is:
2 FeSO4(NH4)2SO4 6H2O + (NH4)2C2O4 + 3 H2SO4 → 2 FeC2O4 + (NH4)2SO4 + 4 H2O
From the balanced equation, you can see that the coefficient in front of FeSO4(NH4)2SO4 6H2O is 2 and in front of FeC2O4 is also 2. This means that for every 2 moles of FeSO4(NH4)2SO4 6H2O that react, 2 moles of FeC2O4 is produced.
So, if you have calculated the moles of FeSO4(NH4)2SO4 6H2O in Step 2, you can multiply it by the ratio of moles of FeC2O4 to moles of FeSO4(NH4)2SO4 6H2O, which is 2/2 = 1.
Step 4: Finally, convert moles of the iron complex to grams using the formula grams = moles x molar mass. The number of grams of the iron complex is the theoretical yield.
To do this, you need to know the molar mass of FeC2O4. You can find the molar masses of the elements from the periodic table and then add them up based on the chemical formula.
Let's say the molar mass of FeC2O4 is 143.9 g/mol.
Multiply the number of moles of FeC2O4 calculated in Step 3 by the molar mass of FeC2O4 to obtain the theoretical yield in grams.
I hope this clarifies steps 3 and 4 for you!