# Physics

A 3600 kg open railroad car coasts along with a constant speed of 11.0 m/s on a level track. Snow begins to fall vertically and fills the car at a rate of 3.70 kg/min.

Ignoring friction with the tracks, what is the speed of the car after 80.0 min?

1. conservation of momentum
Momentum before= momentum after.
3600*11=masssnow*0= (3600+masssnow)Vf

masssnow= 3.7*80 kg
solve for Vf.

posted by bobpursley
2. typo:
3600*11+masssnow*0=(3600+masssnow)*Vf

I hate that key,my pinky always misses +

posted by bobpursley

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