show the algebraic inequality
The profit for a company is determined by the equation y = 0.02x – 0.30, where y represents the profit and x represents the number of items sold. How many items must be sold so that the profit will be at least $4000?
I suspect you have a typo but
solve equality first. Any greater number sold gives more profit.
4000 + .3 = .02x
x = 200,000
so
x>200,000
thank you, that is actually how the word problem was phrased.
To find the number of items that must be sold in order for the profit to be at least $4000, we need to set up an algebraic inequality.
The given equation is: y = 0.02x - 0.30
We want to find the value of x when y is at least $4000. Therefore, we have the inequality:
0.02x - 0.30 ≥ 4000
To solve this inequality, we need to isolate the variable x. Let's start by adding 0.30 to both sides:
0.02x ≥ 4000 + 0.30
0.02x ≥ 4000.30
Next, we want to get rid of the decimal point, so we multiply both sides of the inequality by 100:
100 * 0.02x ≥ 100 * 4000.30
2x ≥ 400030
Now, divide both sides by 2 to isolate x:
2x/2 ≥ 400030/2
x ≥ 200015
Therefore, at least 200015 items must be sold in order for the profit to be at least $4000.