A particle accelerates from rest at 3.1 m/s2.
What is its speed 5.5 s after the particle
starts moving?
Answer in units of m/s.
You take the fact that vi=0, vf=x, delta t=5.5 and a=3.1
i think you use the formula vf=vi + a delta t to find your answer
17.05
To find the speed of the particle 5.5 seconds after it starts moving, we can use the formula for acceleration:
v = u + at
Where:
v = final velocity (speed)
u = initial velocity (in this case, rest, so u = 0)
a = acceleration
t = time
Given that the particle accelerates at 3.1 m/s^2, and the initial velocity is 0, we can plug in these values into the formula:
v = 0 + (3.1 m/s^2) * (5.5 s)
v = 0 + 17.05 m/s
v = 17.05 m/s
Therefore, the speed of the particle 5.5 seconds after it starts moving is 17.05 m/s.