Calculate the theoretical amount of CaCl2 that would be required to change the temperature of 50 mL of water from from temperature 20 degrees Celsius to 45 degrees Celsius. Remember that the heat lost during the dissociation is equal to the heat gained by the 50.0 mL of water. In order to do this, you will need the heat capacity of water. This value is 4.184 J/g-1 and assume that density of water is 1 g/mL
To calculate the theoretical amount of CaCl2 required to change the temperature of 50 mL of water, we need to consider the specific heat capacity of water and the heat transfer equation.
The heat transfer equation is given as:
q = mcΔT
where:
q = heat gained or lost by a substance (in this case, water)
m = mass of the substance (in this case, water)
c = specific heat capacity of the substance (in this case, water)
ΔT = change in temperature
First, we need to calculate the mass of water in grams. Since the density of water is 1 g/mL and the volume is given as 50 mL, the mass of water is 50 g (50 mL * 1 g/mL = 50 g).
Next, we can substitute the known values into the equation:
q = (50 g) * (4.184 J/g-1°C-1) * (45°C - 20°C)
By simplifying, we have:
q = 50 g * 4.184 J/g-1°C-1 * 25°C
Now, we can calculate the heat gained or lost by water:
q = 52,300 J
Since the heat lost by the CaCl2 during its dissociation is equal to the heat gained by the water, we can assume that the amount of CaCl2 required in grams is equal to the heat gained or lost.
Therefore, the theoretical amount of CaCl2 required is 52,300 grams.