In a very simple model of the lower atmosphere, air has a constant density of 1.25 kg/m3. How much would the air pressure change over a height difference of 260 m?
To calculate the change in air pressure over a given height difference, you can use the concept of hydrostatic pressure.
The hydrostatic pressure states that the pressure change in a fluid is directly proportional to the change in height and the density of the fluid. The equation for calculating this change in pressure is:
ΔP = ρgh
Where:
ΔP is the change in pressure
ρ is the density of the fluid
g is the acceleration due to gravity (approximately 9.8 m/s^2)
h is the height difference
Given that the air density is constant at 1.25 kg/m^3 and the height difference is 260 m, we can substitute these values into the equation to find the change in pressure:
ΔP = (1.25 kg/m^3) * (9.8 m/s^2) * (260 m)
Calculating this expression, you find:
ΔP = 3215 Pa
Therefore, the air pressure would change by 3215 Pascal (Pa) over a height difference of 260 m.