could someone check these answer please?
solve the following proportion for x.
x/8=5/3=0
rueben drove 300 miles using 14 gallons of gas, at this rate, how many gallons would he need to drive 210?= 40.3 gallons
solve for v; v^2+v-30=0=v=-6,5
thanks
first one:
x/8 = 5/3
3x = 40
x = 40/3
Your second answer should have appeared illogical to you.
If he uses 14 gal to go 300 miles, how could he use about 3 times that much to go only 210 miles
300/14 = 210/x
300x = 14x210
x = 14x210/300 = 9.8 gallons
third is correct
Thanks again Reiny!!
Sure! I can help you check your answers and explain the process.
1. Solve the proportion for x: x/8 = 5/3.
To solve the proportion, you need to cross-multiply and solve for x.
Cross-multiplying, you get: 3x = 8 * 5.
Multiplying, you get: 3x = 40.
Now, divide both sides by 3 to isolate x: x = 40/3.
So, x ≈ 13.33.
2. Calculate the number of gallons of gas Reuben would need to drive 210 miles.
Given that Reuben drove 300 miles using 14 gallons of gas, you can set up a proportion to find the number of gallons needed for 210 miles.
Let's call the unknown number of gallons y.
The proportion will be: 300 miles / 14 gallons = 210 miles / y gallons.
Cross-multiplying, you get: 300y = 14 * 210.
Multiplying, you get: 300y = 2940.
Now, divide both sides by 300 to isolate y: y = 2940/300.
So, y ≈ 9.8.
Therefore, Reuben would need approximately 9.8 gallons of gas to drive 210 miles.
3. Solve for v in the equation v^2 + v - 30 = 0.
To solve this quadratic equation, you can factor it or use the quadratic formula.
Let's use factoring:
The equation v^2 + v - 30 = 0 can be factored as (v - 5)(v + 6) = 0.
Setting each factor to zero gives two possible solutions:
v - 5 = 0 or v + 6 = 0.
Solving these equations, you get:
v = 5 or v = -6.
So the possible solutions for v are v = 5 or v = -6.
Therefore, your answer v = -6.5 is not correct.
I hope this helps! Let me know if you have any further questions.