Company A charges $55 per day plus $0.35 per mile to rent a car. Company B charges $50 per day plus $0.40 per mile. Jack wants to rent a car for three days. How many miles should Jack be traveling so that Company A is less expensive than Company B?
so 12(8)x ≥ 72
x ≥ 72/96
x ≥ 3/4 ft
To determine how many miles Jack should be traveling so that Company A is less expensive than Company B, we need to compare the total cost for each company.
For Company A:
Total cost = (daily rate × number of days) + (cost per mile × number of miles)
Substituting the given values:
Total cost for Company A = ($55 × 3) + ($0.35 × number of miles)
For Company B:
Total cost = (daily rate × number of days) + (cost per mile × number of miles)
Substituting the given values:
Total cost for Company B = ($50 × 3) + ($0.40 × number of miles)
To find the point where Company A is less expensive than Company B, we need to set up an equation and solve for the number of miles:
($55 × 3) + ($0.35 × number of miles) < ($50 × 3) + ($0.40 × number of miles)
Simplifying the equation:
$165 + $0.35 × number of miles < $150 + $0.40 × number of miles
Subtracting $150 and $0.35 × number of miles from both sides of the equation:
$165 - $150 < $0.40 × number of miles - $0.35 × number of miles
$15 < $0.05 × number of miles
Dividing both sides of the equation by $0.05:
$15 / $0.05 < number of miles
300 < number of miles
Therefore, Jack should be traveling more than 300 miles so that Company A is less expensive than Company B.
A: cost= 3*55+.35m
B: cost=3*50+.40m
set the costs equal, and solve for m.